2x^2+15x+27=0.

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Solution for 2x^2+15x+27=0. equation: 



2x^2+15x+27=0.

a = 2; b = 15; c = +27;
Δ = b2-4ac
Δ = 152-4·2·27
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$


$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-3}{2*2}=\frac{-18}{4}
=-4+1/2
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+3}{2*2}=\frac{-12}{4}
=-3
$

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